Question

ANSWER A, B & C OF QUESTION. SHOW WORK

IP A magician wishes to create the illusion of a 2.69-in-tall elephant. He plans to do this by forming a virtual image of a 45.0-cm-tall model elephant with the help of a spherical mirror. You may want to review (Pages 923 - 928). Part A Should the mirror be concave or convex? concave o convex Submit Request Answer Part B If the model must be placed 3.35 m from the mirror, what radius of curvature is needed? EVO AMO ? Submit Request Answer Partc How far from the mirror will the image be formed? V AXC + + O ?

Answer 1

A) convex

Because, a virtual image formed by a concave mirror is always magnified.

B)

magnification, m = image height/object height

= 0.45/2.69

= 0.1673

let u and v are object and image distances.

we kknow, m = -v/u

v = -m*u

= -0.1673*u

let f is the focal length of the mirror.

now use, 1/u + 1/v = 1/f

1/3.35 + 1/(-0.1673*3.35) = 1/f

==> f = -0.673 m

we know, R = 2*|f|

= 2*0.673

= 1.35 m <<<<<<<<<----------------------Answer

C)

now use, 1/do + 1/di = 1/f

1/di = 1/f - 1/do

1/d = 1/(-0.673) - 1/3.35

di = -0.560 m <<<<<<<<<----------------------Answer