Question

A big olive (m=0.11 kg) lies of an xy coordinate system, and a Brazil nut (M=0.84 kg0 rightarrow F0 = (3.2i + 4.9j) N begins to act on the olive , and a force rightarrow FN = (-2.7i-3.6j)N begins to centre of mass of the olive -nut system at t=4.1 s, with respect to its position at t=0? Number units Number units

Answer 1

Given that,

mo = 0.11 kg ; mn = 0.84 kg ; (1.2,4.0)m

Fo = 3.2 i + 4.9 j and Fn = -2.7 i - 3.6j

lFol = 5.6 N ; lFnl = 4.5 N

We know that, F = m a => a = F/m

ao = Fo/mo = 5.6/0.11 = 51 m/s²

an = Fn/mn = 4.5/0.84 = 5.36 m/s²

The intial velocity of COM is 0. From equation of motion we know that,

S = ut + 1/2 a t²

Do = 1/2 x ao t²

Do = 0.5 x 51 x 4.1² = 428.66 m

Dn = 1/2 an t²

Dn = 0.5 x 5.36 x 4.1² = 45.05 m