Question

A 7600 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.15 m/s2 and feels no appreciable air resistance. When it has reached a height of 530 m its engines suddenly fail only force acting on it is now gravity. Previous Answers Submit that the Correct Part B How much time after engine failure will elapse before the rocket comes crashing down to the launch pad? ν ΑΣφ. ? t = S Request Answer Submit Part C How fast will it be moving just before it crashes? Πνα ΑΣΦ ? m/s Request Answer Submit

Answer 1

B According to Newtons equation of Motion S=ut that? 530 = 0.t+ £ 12:15)ť? >) t = 1060/2.15 = 493.02 =) t=22.20 sec

c) S=ut+l at =) 530 = 0 +(9.8)t/ 7 ²-530/4.93t-10.40 sec Now U=u-gt , uto v=- 9.8*10.405 v= 101.92m/s