Question

5. A basic generator is shown below. The static magnetic field is given by B = B.â, where B. = 0.2 T. The area A of the loop is A = 0.1 m², and it is spinning about the x-axis as indicated at 3600 revolutions per minute (rpm). có 2000 pa a. Find the time-dependent magnetic flux (t) linking the loop. b. Find the resulting Vemf. c. Find the current through the 100-2 light bulb

Answer 1

Given data

Max flux density B=0.2T , area of the loop A=0.1 m(square), N speed= 3600rpm

Z=2 (since one simple coil consists two conductors) resistance R=100 ohms

P=2( since no of poles= no of brushes )

A=2(no of parallel paths are Two)

Q1. Flux= Area*Flux density =0.1*0.2=0.02 Webers

Q2. VemF= $\phi$ ZN P divided by 60*A =0.02*2*3600*2 divided by 60*2=2.4 volts

Q3. We know by ohms law V= I*R

I=V/R =2.4/100 =24 mA