Question

The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.6 967 99.8 97.2 98 98.8 98 964 99.2 99.3 Assume body temperatures of adults are normally distributed. Based on this data, find the 80% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 1 decimal place. Assume the data is from a normally distributed population. 80% CI,- Preview

Answer 1

Answer)

As, population standard deviation is unknown here, we need to use t distribution table to construct the confidence interval

First we need to estimate the sample mean and sample standard deviation of the given data

Mean = 98.25

Standard deviation (s.d) = 1.1492

From t table, for degrees of freedom n-1, 10-1, 9 and 80% confidence level, critical value t is = 1.383

Margin of error (MOE) = t*(s.d/√n)

1.383*(1.1492/√10)

= 0.50259457606

Confidence interval is given by

Mean - MOE, mean + MOE

MOE = margin of error

97.7474054239, 98.7525945760

97.7, 98.8