Part(1)
*u = initial velocity.
*d = distance traveled = 8 - 2 = 6 m.
*t = time interval = 2.5 s.
*v = final velocity = 2.8 m/s.
*a = acceleration.
Now using the formula of kinematics,
Subtract eqn1 from eqn2,
Part(2)
*.
x - cordinate =
y-coordinate =
Part(3)
Part(4)
*
*u = initial velocity =
*x = final position after time t = 2 s.
Now writing the equation for motion,
Distance from origin after t = 2 s, = 18 m.
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