The equilibrium bond length in nitric oxide (14N 16O) is 1.15 Å. a. Calculate the moment...
The equilibrium bond length in nitric oxide (14N 16O) is 1.15 Å.
a. Calculate the moment of inertia of nitric oxide.
b. Calculate the energy of ? = 0 → 1 transition.
c. How many times NO rotates per second in its first rotationally excited state?
d. How many degenerate states are associated with the sixth rotationally excited state (ignoring the potential degeneracies associated with the electronic and vibrational states)?
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The equilibrium bond length in nitric oxide (14N 16O) is 1.15
Å.
a. Calculate the moment...
Having trouble with a & c The equilibrium bond length in oxygen gas (602) is 1.21...
Having trouble with a & c
The equilibrium bond length in oxygen gas (602) is 1.21 Å. (Use the relative atomic mass: 160 = 15.994914622.) (a) Calculate the moment of inertia of 1602 40 4.68e-22 1.94e-46 kg'm2 |X 0 transition. (b) Calculate the energy for the J 1 4.0 5.73e-23 5.72e-23 (c) How many times does the molecule rotate per second in the J 1 level? 40 2.73e8 8.63e+10 s~1
(30) Given the equilibrium bond length of CO is 1.138, explore population fractions (Eq. 2) of...
(30) Given the equilibrium bond length of CO is 1.138, explore population fractions (Eq. 2) of the ground state and first 15 pure rotational excited states relative to the ground state (where {=0). Mathematica is recommended. Do this at 298 K and at 100 K. Comment on how the results differ compared to part a). 1) In the application of quantum mechanical and statistical mechanical principles to samples containing large numbers of species (e.g. macroscopic samples of molecules), there is...
Having trouble with a & c
The equilibrium bond length in oxygen gas (602) is 1.21 Å. (Use the relative atomic mass: 160 = 15.994914622.) (a) Calculate the moment of inertia of 1602 40 4.68e-22 1.94e-46 kg'm2 |X 0 transition. (b) Calculate the energy for the J 1 4.0 5.73e-23 5.72e-23 (c) How many times does the molecule rotate per second in the J 1 level? 40 2.73e8 8.63e+10 s~1
(30) Given the equilibrium bond length of CO is 1.138, explore population fractions (Eq. 2) of the ground state and first 15 pure rotational excited states relative to the ground state (where {=0). Mathematica is recommended. Do this at 298 K and at 100 K. Comment on how the results differ compared to part a). 1) In the application of quantum mechanical and statistical mechanical principles to samples containing large numbers of species (e.g. macroscopic samples of molecules), there is...
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