Question

A charge of 23.8 is located at (4.33 m, 5.97 m), and a charge of -12.0...

A charge of 23.8 $\mu C$ is located at (4.33 m, 5.97 m), and a charge of -12.0 $\mu C$ is located at (-4.53 m, 6.77 m). What charge must be located at (2.11 m, -2.92 m) if the electric potential is to be zero at the origin?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

For 1st charge, distance to origin = sqrt(4.33^2 + 5.97^2 ) = 7.375m
For 2nd charge, distance to origin = sqrt(4.53^2 + 6.77^2 ) = 8.146m
For 3rd charge, distance to origin = sqrt(2.11^2 + (-2.92)^2) = 3.602m

Potential at origin from 1st charge = kQ/r = k x 23.8x10^-6 / 7.375
Potential at origin from 2nd charge = kQ/r = k x (-12.)x10^-6 / 8.146
Potential at origin from 3rd charge = kQ/r = k x Q x10^-6 /3.602 where Q is in microC

Potential is a scalar, so you can just add the values to get the total; we want total at origin to be zero so:
[k x 23.8x10^-6 / 7.375 ] + [k x (-12.)x10^-6 / 8.146 ] + [ k x Q x10^-6 /3.602] = 0
23.8/7.375 - 12/8.146 + Q/3.602 =
1.754 + Q/3.602 = 0
Q = -1.754x3.602 = - 6.318microC

Add a comment
Answer #3

For 1st charge, distance to origin = sqrt(4.33^2 + 5.97^2 ) = 7.375m
For 2nd charge, distance to origin = sqrt(4.53^2 + 6.77^2 ) = 8.146m
For 3rd charge, distance to origin = sqrt(2.11^2 + (-2.92)^2) = 3.602m

Potential at origin from 1st charge = kQ/r = k x 23.8x10^-6 / 7.375
Potential at origin from 2nd charge = kQ/r = k x (-12.)x10^-6 / 8.146
Potential at origin from 3rd charge = kQ/r = k x Q x10^-6 /3.602 where Q is in microC

Potential is a scalar, so you can just add the values to get the total; we want total at origin to be zero so:
[k x 23.8x10^-6 / 7.375 ] + [k x (-12.)x10^-6 / 8.146 ] + [ k x Q x10^-6 /3.602] = 0
23.8/7.375 - 12/8.146 + Q/3.602 =
1.754 + Q/3.602 = 0
Q = -1.754x3.602 = - 6.318microC

Add a comment
Know the answer?
Add Answer to:
A charge of 23.8 is located at (4.33 m, 5.97 m), and a charge of -12.0...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT