Question

Equations E= 1 gd 2tso 23 1 P and E = are approximations of the magnitude of the electric field of an electric dipole, at points along the dipole axis. Consider a point P on that axis at distance z4.00d from the dipole center (where d is the separation distance between the particles of the dipole). Let Eappr be the magnitude of the field at point P as approximated by 160 and E-2πε023 (electric dipole). Let Eact be the actual magnitude. By how much is the ratio Eapp Eact less than 1?

1 0
Add a comment Improve this question Transcribed image text
Answer #1

Given, z: 4 ood. 2 actuel 2 2 (0.0322) 45 and 2d .03(2) appo 2 2. Eact

Add a comment
Know the answer?
Add Answer to:
Equations E= 1 gd 2tso 23 1 P and E = are approximations of the magnitude...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 7. 0/1 points | Previous Answers HRW10 22.P.020. My Notes Equations E = 21 and E...

    7. 0/1 points | Previous Answers HRW10 22.P.020. My Notes Equations E = 21 and E = 210,7 are approximations of the magnitude of the electric field of an electric dipole, at points along the dipole axis. Consider a point P on that axis at distance z = 4.50d from the dipole center (where d is the separation distance between the particles of the dipole). Let Eappr be the magnitude of the field at point P as approximated by E'...

  • Electric dipole

    Equations 22-8 and 22-9 are approximations of the magnitude of the electric field of an electric dipole, at points along the dipole axis. Consider a point P onthat axis at distance z = 7.00d from the dipole center(where d is the separation distance between the particles of the dipole). Let Eappr be the magnitude of thefield at point P as approximated by Equations 22-8 and 22-9. Let Eact be the actual magnitude. By how much is the ratio Eappr/Eact less...

  • EQUATIONS 22-7, 22-8, 22-9, listed below 22-7: 22-8: 22-9: since qd=p the magnitude of electric dipole...

    EQUATIONS 22-7, 22-8, 22-9, listed below 22-7: 22-8: 22-9: since qd=p the magnitude of electric dipole moment vector, direction p taken from negative to positive end of dipole 18 The electric field of an electric dipole along the dipole axis is approximated by Eqs. 22-8 and 22-9. If a binomial expansion is made of Eq. 22-7, what is the next term in the expression for the di pole's electric field along the dipole axis? That is, what is Enext in...

  • A dipole is located at the origin, and is composed of charged particles with charge e...

    A dipole is located at the origin, and is composed of charged particles with charge e and -e, separated by a distance 2 10-10 m along the x axis. The positive x axis points to the right. The te charge is on the positive x-axis. Suggestion: draw a picture with the dipole and the observation location (where you want to find the field). What is the magnitude of the electric field due to this dipole at location 〈 0,2 *...

  • Tipler6 23.P.085. Along the axis of a uniformly charged disk, at a point 0.6 m from...

    Tipler6 23.P.085. Along the axis of a uniformly charged disk, at a point 0.6 m from the center of the disk, the potential is 56.9 V and the magnitude of the electric field is 63.2 V/m; at a distance of 1.5 m, the potential is 27.1 V and the magnitude of the electric field is 16.5 V/m. Find the total charge residing on the disk.

  • Tipler6 23.P.085. Along the axis of a uniformly charged disk, at a point 0.6 m from...

    Tipler6 23.P.085. Along the axis of a uniformly charged disk, at a point 0.6 m from the center of the disk, the potential is 56.9 V and the magnitude of the electric field is 63.2 V/m; at a distance of 1.5 m, the potential is 27.1 V and the magnitude of the electric field is 16.5 V/m. Find the total charge residing on the disk.

  • Both in class and in Knight (p. 633) it was shown that the electric field of...

    Both in class and in Knight (p. 633) it was shown that the electric field of an electric dipole far along the dipole axis is given by 2kp In the second problem of PS2 (Knight Chapter 23, Problem 3) you determined the electric field of a specific electric dipole at a specified point along the bisecting plane of the dipole. Repeat this calculation for an electric dipole with an unspecified charge q and show that the electric field very far...

  • A dipole is located at the origin, and is composed of charged particles with charge e...

    A dipole is located at the origin, and is composed of charged particles with charge e and -e, separated by a distance 2 10-10 m along the x axis. The positive x axis points to the right. The te charge is on the positive x-axis. Suggestion: draw a picture with the dipole and the observation location (where you want to find the field). What is the magnitude of the electric field due to this dipole at location 〈 0,2 *...

  • 8.Show that at points along the axis of a dipole (along the line joining the two charges), the el...

    8.Show that at points along the axis of a dipole (along the line joining the two charges), the electric field has magnitude 1 2p for rl, where r is the distance from a point to the center of the dipole. Indicate the direction in which E point. Note that there is an extra factor of two in the equation above, which differs from Eq. 21-12. Hint: Use binomial approximation. If you don't know it, please look it up! 8.Show that...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT