Homework Answers
1)some balls are not in any box
3ball(x) -> ~box(x). ( Think 3 as inverted E)
2)every box hax some balls in it
¥box(x) => ball(x). (Think ¥ as inverted A)
3)A ball cannot have more than one color:
∃(x) [ ball(x) → color (x, y1) ∧∀ ball(x)→ ¬color (x, y1)].
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