5. (20 pts.) The molar heat capacity CP.m of H2O(g) from 373 K to 473 K...

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Question

Answer 1

Answer #1

b.) Calculation of $\Delta U$ ,

Since H = U + PV,

hence $\Delta H = \Delta U +\Delta PV \Rightarrow \Delta U +nR\Delta T$ , ( substituting PV = nRT from ideal gas behaviour)

$\Delta U = \Delta H -nR\Delta T$ ,

$\Delta U$ = 3489.69 J - 1mol X 8.314JK-1mol-1 X (473-373)K

$\Delta U$ = 3489.69J - 831.4J = 2658.29 Jmol-1 Or 2.658 KJmol-1

Answer 2

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