Question

Suppose that we have found that in Jill’s remote log-ins to a certain computer, the number...

Suppose that we have found that in Jill’s remote log-ins to a certain computer, the number X of disk sectors she reads or writes has an approximate normal distribution with a mean of 500 and standard deviation of 15.

Say we’ve set our network intrusion monitor to notify us every time Jill logs in and accesses 535 or more disk sectors.

In what proportion of all such notifications will Jill have accessed at least 545 sectors?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution:

Given, the Normal distribution with,

  \mu = 500

\sigma = 15

Find P(at least 545 sectors)

P(X \geq 545) = P[(X - \mu )/\sigma >  (545 - \mu )/\sigma]

= P[Z > (545 - 500)/15]

= P[Z > 3.00]

= 1 - P(Z < 3.00)

= 1 -   0.9987 ...use z table

=  0.0013

Add a comment
Know the answer?
Add Answer to:
Suppose that we have found that in Jill’s remote log-ins to a certain computer, the number...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Suppose that we have found that in Jill’s remote log-ins to a certain computer, the number...

    Suppose that we have found that in Jill’s remote log-ins to a certain computer, the number X of disk sectors she reads or writes has an approximate normal distribution with a mean of 500 and standard deviation of 15. Say we’ve set our network intrusion monitor to notify us every time Jill logs in and accesses 535 or more disk sectors. In what proportion of all such notifications will Jill have accessed at least 545 sectors?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT