Question

Solve the following problems. 1. Convert 9.30 moles CH, to grams. 9. 30 2. Convert 38.0 grams CaCl, to moles. 3. Convert 3.00 moles NH, to molecules. 4. Convert 2.08 x 10" formula units KCIO, to moles. DO 5. Convert 2.20 x 10” molecules of CH3COOH to grams. 6. Convert 25.3 grams of Ca (AsO4)2 to formula units.

Answer 1

Answer 1 -

Given,

Moles of CH₄ = 9.30 mol

Molar Mass of CH₄ = 16.04 g/mol

Mass of CH₄ = ?

We know that,

Moles = Mass / Molar Mass

Mass = Moles * Molar Mass

Mass of 9.30 mol of CH₄ = 9.30 mol * 16.04 g/mol

Mass of 9.30 mol of CH₄ = 149.172 g [ANSWER]

Answer 2 -

Given,

Mass of CaCl₂ = 38.0 g

Molar Mass of CaCl₂ = 110.98 g/mol

Moles of CaCl₂ = ?

We know that,

Moles = Mass / Molar Mass

Moles of 38.0 g of CaCl₂ = 38.0 g / 110.98 g/mol

Moles of 38.0 g of CaCl₂ = 0.3424 mol [ANSWER]

Answer 3 -

Moles of NH₃ = 3.00 mol

Molecules = ?

We know that,

1 mole = 6.022 * 10²³ molecules

So, molecules of 3.00 mol of NH₃ = 3.00 * 6.022 * 10²³ molecules

molecules of 3.00 mol of NH₃ = 18.066 * 10²³ molecules [ANSWER]

Answer 4 -

Given,

Formula Units of KClO₄ = 2.08 * 10²⁵ formula units

Moles = ?

We know that,

1 mole = 6.022 * 10²³ formula units

So, 1 formula units = (1/6.022) * 10^-23 mol

1 formula units = 0.16606 * 10^-23 mol

So, 2.08 * 10²⁵ formula units of KClO₄ = 2.08 * 10²⁵ * 0.16606 * 10^-23 mol

2.08 * 10²⁵ formula units of KClO₄ = 34.5405 mol [ANSWER]