![Accepted characters For the reaction 3NO → N2O + NO2, the following data were collected: t(min) [NO] In[NO] 1/[NO] 0.01 4.605](http://img.homeworklib.com/questions/fb783b40-cd43-11ea-9485-272e3967d0a9.png?x-oss-process=image/resize,w_560)
Homework Answers
3 NO ==> N2O + NO2
In this case , our graph with the inverse of the concentration, 1/[NO] versus time, we get a positive straight line with a positive slope : it's second order reaction.
== Order of reaction in NO : 2
== rate constant k, ==> slope = (278.7879 M-1 / 360 min) = 0.774 M-1s-1 k ==> k = 0.774 M-1min-1
== 2nd order reaction Half like = 1/k[NO]0 = 1/ 0.774 M-1min-1*0.01 M = 129 Min
===
from 2nd order kinetics at 100 min.
1/[NO] = 1/[NO]0 + kt = 100 M-1 + 77.4 M-1
[NO] = 0.00564 mol/L
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Accepted characters For the reaction 3NO...
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