given
I1 = 7.15 A
I2 = -2.10 A
I3 = 7.15 A
d = 3.03 cm 0.0303 m
at origin magnitude of magnetic field due to I1,
B1 = mue*I1/(2*pi*d)
= 4*pi*10^-7*7.15/(2*pi*0.0303)
= 4.72*10^-5 T
at origin magnitude of magnetic field due to I2,
B2 = mue*I2/(2*pi*sqrt(2)*d)
= 4*pi*10^-7*2.1/(2*pi*sqrt(2)*0.0303)
= 0.980*10^-5 T
at origin magnitude of magnetic field due to I3,
B3 = mue*I3/(2*pi*d)
= 4*pi*10^-7*7.15/(2*pi*0.0303)
= 4.72*10^-5 T
x-compoment of net magneti field,
Bnetx = B1x + B2x + B3x
= 0 - 0.980*10^-5*cos(45) + 4.72*10^-5
= 4.03*10^-5 T
y-compoment of net magneti field,
Bnety = B1y + B2y + B3y
= -4.72*10^-5 + 0.980*10^-5*cos(45) + 0
= -4.03*10^-5 T
so, net magnetic field at origin,
Bnet = Bnetx i + Bnety j
= 4.03*10^-5 i - 4.03*10^-5 j <<<<<<----------Answer
Note : please comment of any further clarification.
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