Question

3. For the bulb shown below calculate fraction of the radiation in the visible range (0.4<<0.50) if the bulb filament temperature is 2500 °K. (20 points) 0 754140 0769234 0 83199 o 7% 129 0 808109 0 000016 o 000321 002134 0 007790 0 019718 0 039341 0 066728 0 100888 0 140256 0 183120 0227897 0 273232 0 318102 361735 0 403607 0 443382 0 480877 0 516014 0 548796 0 579280 0 607559 0 633747 0 658970 1000 1200 1400 1600 1800 200 400 0 829527 0 839102 0 84800! 0 856288 0 874608 0 890029 0 903085 0914199 0 923710 0 931890 0.939955 0 943098 0 955139 0 962898 0 969981 0 973814 0 9808640 0 985602 0 992215 0 995340 0 997967 2200 8500 2800 0.000 10,500 11.000 11,500 12.000 13,000 14.000 15.000 16.000 18,000 20000 25,000 3000 40.000 50.000 5,000 100.000 T= 2500 K 3400 4800 5400 0 701046 О 720158 。737818 998953 0 999713

Answer 1