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A rectangular bar of aluminum (2014-T4) has a length of 2.400 m and cross-sectional dimensions of...

A rectangular bar of aluminum (2014-T4) has a length of 2.400 m and cross-sectional dimensions of 25 mm x 50 mm when the temperature is 20 C.

a. At what temperature would the length be 2.405 m if the bar is unrestrained?

b. If the temperature is increased an additional 30 C while the bar is restrained from growing lengthwise, compute the resulting stress in the bar.

c. Is the stress level safe?

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Answer #1

li=2.400m lf 2.405m (&) al = 238106 @ we know Alli & At 0.005= 2.4 x 23 x 100 x (Tf - 20 () Al = 0.005 m Tf=90.57 + 20 Tf = 1I have solved the question step by step and neatly so that you can understand the solution easily and efficiently. Hope you thumpsup for the efforts. Thank you.

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