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Show that if 0 < μ < 2-r has a unique relative extreme (max) value for x in (0,1)
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Any query then comment below..

For maxima , we firstly find critical point by taking first derivative equal to 0...then show that second derivative is negative..

2 2.dメNow as

Here we see that when value of nu is between 0 and 2 ... Then second derivative is maximum at x= 1/2 ...and this extreme value of x lies in (0,1) ..

So our result is proved

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