Question

A certain hydrochloric acid solution has a mole fraction of 0.23 HCI. the density of this solution is 1.18g/mL

a. how many moles of HCI are in 1 mole of solution?

b. what is the weight percent of HCI in this solution?

c. what is the molarity of HCI in this solution?

d what is the molality of HCI in this solution?

e. what is the weight percent of water in this solution?

f. what is the mole fraction of water in this solution?

Answer 1

Mole fraction of hcl = 0.23 density = 1.18 g/ml water density = 1.0 g/mol (standard) a) number of mples Of HCL in mole solution mole fraction = number of moles of HCl/ total number of solution 0.23 = number of moles of Hairy cell leukemia1 mole number of moles of Hcl = 0.23 moles b) weight percent of Hcl: = weight Hcl weight of solution Hcl/weight of solution times 100 = (weight of solution - weight of reaction/weight of solution) times 100 = (1 - weight of solutes /weight of solution) times 100 weight of water = density of water times volume weight of solution = density of solution times volume weight % = (1 - 1.0g/m(x vml/1.1 belongs to ml times ml) times 100 = (1 - 1/1.18) times 100 = 15.25% ans: 15.25%