Question

Q2: A normally consolidated clay sample is tested under uniaxial (unconfined) compession. Unconfined compressive strength was found as qu=1.80 kg/cm². It is known from previous drained triaxial tests that, '=30°. A) What would be the pore pressure at failure durin unconfined testing?, B) Without changing water content, if you carry out an unconsolidated-undrained triaxial test on the same sample, calculate maximum principle stres values for 0;= 3 kg/cm², 03= 3.5 kg/cm², 0;= 4 kg/cm².

Answer 1

93=0 (in uc Test) (A) Given q = 1.8 Kg/cm qu=107) = 1.8 181 cm? by the relation :- o = S3 tan2 (45+4) In terms of effective abess we can cosite ol= og tan? (45+ pl] where 5 = - =T-U = 1,8-v oz!= 13-U = 0-4 =-a (1.8-u) = (-u) tan2 (45+30) 1.8-v= -ux3 1.8= - Butu= -20 U= Pose Pressure at fall ise = -0.9 Kg ) ani? (B) if Oz = 3 kg ( cm2 then l=%-U=3-(-0.9) Og'= 3.9kg/cm2 ol= og' tan" (45+61 or = 3.9 fan2 (45+30) = 11.7 Kg/cm2 r=1' to = 11.7+(-0.9)=10.8 Kg/cm2

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