Question

ICA 8-18 (algorithmic) You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles (mol) of 19 grams (g) of this compound. The compound has the formula: XY226, where the components are X, amu = 49, Y. amu = 43, Z, amu = 19.

Answer 1

The given compound is X₂Y₂Z₆

Given molar mass of X = 49 amu

Molar mass of Y = 43 amu

Molar mass of Z = 19 amu

These are the atomic mass units and are equal to 1 mole of the atoms when taken in grams.

For example, 49g of X is usually present in 1 mole of X.

Therefore the molar mass of X₂Y₂Z₆

= (2×49) + (2×43) + (6×19) = 98 + 86 + 114 = 298 g/mol

Therefore one mole of X₂Y₂Z₆ is present in 298g of this molecule.

1 mole is present in 298g

? moles are present in 19g

Therefore 19g of compound is present in

19/298 = 0.06376 moles.

This the required number of moles of compound present in 19 grams of X₂Y₂Z₆ are 0.06376 moles.