Question

In the circuit of (Figure 1), each resistor represents a light bulb. Let R = R = R = R = 4.44 12 and let the EMF be 8.90 V.

Bulb RA is now removed from the circuit, leaving a break in the wire at its position. What is the current in the bulb R? Expr

Bulb R4 is now removed from the circuit, leaving a break in the wire at its position. What is the current in the bulb R ? Exp

Bulb RA is now removed from the circuit, leaving a break in the wire at its position. What is the current in the bulb Rz? Exp

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Answer #1

After Ry is removed from the circuit. The cincuit becomes Ri - Now the resistons R₂ & Rq one in panallel so the equivalent re1. The eurnent in the bulb R₂ is - -- ५. ५५ ___ x 1.336 ५.५५+५.५५ - 0.663 A The current in the bui -RT- x 1.336 4.44 - - ५.५५

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