Question

The components in this network have values R = 2.8 k 2, L = 50 mH, and C = 16 UF. RL Wm (a) Determine the real and imaginary parts of the network's impedance Z (in 2), as functions of the angular frequency w in rad/s). Use omega as the variable name Re{Z} = Im{Z} = (b) At what value of cyclical frequency f is z purely real? Hz (c) What is the value of Z at this special frequency? Ω tsymbolic formatting help +-/3 points The components in this network have values R = 4.8 k 2, L = 36 mH, and C = 10 uF. R W (a) Determine the real and imaginary parts of the network's impedance Z (in 2), as functions of the angular frequency (in rad/s). Use omega as the variable name Re{Z} = Im{Z} = (b) At what value of cyclical frequency f does 2 00? Hz

Answer 1

Given Given & am R=2.84s2, LE SOMH, C = 16 MF a) In a series R-L-c circuit The current across all the terminals are const

2= Rt jul to moc - R+jwL- z z R+ j(WL-a Recz) = R2 = 2.8K2) img1z) = (WL- 1 c) or - w 150m) - incias imgczy coor (800n) - 17 Will M Taloon

b. The frequency at which the z'is real is given 1 = R+} (WL- loc) if ing teem is equal to zelo then the impedence is pure real w Lot Loco we = b = won the wc The requency [t= and at which L 2i8 real. for to If = 177.9406 H2 . (C)' The value of 2 at 2= R = 2.8K-2 f=177.94 is

R-48122, L=36MH, CE1OME To deteemine assume an the impedence of theckt current souce I as 8owice I= Iltic I FIRA It is the Vi er en TEVE ) the I=NCY) Where admitance 4 = ilt =)

impedence (AC-1/4 j 12. . Real paet = 0 imppact = k) The frequency * at which zudig =0 %= the sX2=Xc WL= f=/ RTAL t = 265.258 HZ