Question

In the C language,

Write a program that inputs 4 hexadecimal digits as strings (example 7F), converts the string digits to a long – use strtol(input string,&ptr,base) to do the conversion. Just declare ptr as a char ptr, don’t worry about what it does. Copy each converted number [ a long] into unsigned char’s [like the variable num1 below – hint: cast a long variable into the unsigned char’s] before performing the following logical operations on them (parenthesis might help, since things should be executed from left to right): result=num1 and num2 or num 3 exclusive or num4 print out result in capital hex

Answer 1

#include<stdio.h>

char arr[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};

long strtol(char string[10],char *ptr,int base){
  
  
   char ch=*ptr;
   long i;
   for(i=0;i<16;i++){
       if(arr[i]==ch){
           break;
       }
   }

   return i;
}

void print(long result){
   if(result==0)
       return;
   print(result/16);
   int val=result%16;
   printf("%c",arr[val]);
   return;
}

int main(){
   //ios::sync_with_stdio(0);
   //cin.tie(0);
   //write your code here
   char str[10];
   long result;
   long num1,num2,num3,num4;

   scanf("%s",str);
   num1=strtol(str,&str[0],10);
   num2=strtol(str,&str[1],10);
   num3=strtol(str,&str[2],10);
   num4=strtol(str,&str[3],10);
   result=num1 & num2 | num3 ^ num4;
   print(result);
   printf("\n");
   return 0;
}