Solution:
Here, we have to use chi square test for independence of two categorical variables. The null and alternative hypothesis for this test is given as below:
Null hypothesis: H0: The response of the subject and the gender of the subject are independent.
Alternative hypothesis: Ha: The response of the subject and the gender of the subject are dependent.
(Correct answer: A)
We are given
Level of significance = ? = 0.05
Test statistic formula is given as below:
Chi square = ?[(O – E)^2/E]
Where, O is the observed frequencies and E is expected frequencies.
Calculation tables are given as below:
Chi-Square Test |
||||||
Observed Frequencies |
||||||
Column variable |
Calculations |
|||||
Row variable |
Men |
Women |
Total |
(O - E) |
||
Agree |
424 |
250 |
674 |
-47.8 |
47.8 |
|
Disagree |
276 |
50 |
326 |
47.8 |
-47.8 |
|
Total |
700 |
300 |
1000 |
|||
Expected Frequencies |
||||||
Column variable |
||||||
Row variable |
Men |
Women |
Total |
(O - E)^2/E |
||
Agree |
471.8 |
202.2 |
674 |
4.842815 |
11.2999 |
|
Disagree |
228.2 |
97.8 |
326 |
10.01245 |
23.36237 |
|
Total |
700 |
300 |
1000 |
Chi square = ?[(O – E)^2/E] = 49.51753
Number of rows = r = 2
Number of columns = c = 2
Degrees of freedom = (r – 1)*(c – 1)
Degrees of freedom = (2 – 1)*(2 – 1)
Degrees of freedom = 1*1 = 1
Critical value = 3.841459
P-value = 0.0000
(Critical value and P-value is calculated by using Ti-84 calculator. In Ti-84 calculator, press 2nd > VARS to get the DISTR menu. Scroll down to Chi square and select pdf/cdf/inv function according to find critical/P-value and press enter. Enter the values of Chi square statistic and degrees of freedom.)
? = 0.05
P-value < ? = 0.05
So, we reject the null hypothesis that the response of the subject and the gender of the subject are independent.
There is sufficient evidence to conclude that the response of the subject and the gender of the subject are dependent.
Please show how to answer using TI 84 caculator. The question ask to compute the test...
Test Statistic =
Score: 0.33 of 1 pt 3 of 10 (10 complete) HW Score: 45.83%, 4.58 of 10 pts 2x) 11.2.7 Question Help The table below summarizes data from a survey of a sample of women. Using a 0.05 significance level, and assuming that the sample sizes of 700 men and 300 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does...
Please also answer: P-value: found to four decimal
places:
Thank you!
The table below summarizes data from a survey of a sample of women. Using a 0.01 significance level, and assuming that the sample sizes of 800 men and 300 women are predetermined, test the claim that the proportions of agree/disagree responses are the same for subjects interviewed by men and the subjects interviewed by women. Does it appear that the gender of the interviewer affected the responses of women?...