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(25%) Problem 2: Consider a heat engine with a cycle described by the figure, with the (10 N/m2) volume and pressure at points A. B. C, and D given below Randomized Variables VA 1.15 x 10-3 m3 PA 2.5 x 106 N/m2 PB 2.12 x 106 N/m2 PC = 0.45 × 106 N/m2 P 0.93 x 106 N/m2 Va V (10-*m) Otheexpertta.com Calculate the net work output, in joules, of the heat engine following path ABCDA Grade Summarv Deductions Potential 0% 100% cosO asin atan) acotan sinh) Submissions Attempts remaining: 5 (2% per attempt) detailed view sinO tan cotan a acosO coshO tanh cota 0 Degrees Radians Submit Hint I give up! Hints: 1 % deduction per hint. Hints remaining: 4 Feedback: 1% deduction per feedback.

Answer 1

Work done w = Area of ABCDA Area of ABC, A_1 = 1/2 (v_B - V_A) (p_A - p_B) A_1 = 1/2 [(3.1 - 1.15) times 10^-3] [(2.5 - 2.12) times 10^6] = 370.5 J Area of Rectangle EBCF is A_2 = (v_B - v_A) (p_B - p_C) A_2 = [(3.1 - 1.15) times 10^3] [(2.12 - 0.45) times 10^6] = 3256.5 J Area of DCF is, A_3, A_3 = 1/2 (v_B - v_A) (p_D - p_C) = 1/2 [(3.1 - 1.15) times 10^-3] [(0.93 - 0.45) times 10^6] = 468 J Therefore W = A_1 + A_2 - A_3 = 3159 J