Question

A Hydraulic Pump Due this Friday, Nov 13 at 11:59 pm (EST) Piston 1 in the...

A Hydraulic Pump

Due this Friday, Nov 13 at 11:59 pm (EST)

Piston 1 in the figure below has a diameter of 0.770 cm;

A Hydraulic Pump Due this Friday, Nov 13 at 11:59
piston 2 has a diameter of 3.30 cm. In the absence of friction, determine the force required on piston 1 necessary to support an object, m, with weight 840 N. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).

Tries 0/10

What is the magnitude of the force, F, required at the end of the handle?

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Answer #1

at the ends of fluid, pressure will be same.

and P = F/A = constant

so F1 /A1 = F2 / A2

( F1 / (pi (0.770/2)^2)) = (840 / (pi (3.30/2)^2))

F1 = 45.73 N .......Ans (force at 1)


--------------------------

balancing moment (r x F )aboutpivoted point ,


( 2 x F1) - ( (2+10) x F) =0

F = (2 x 45.73) / 12 = 7.62 N ......Ans ( at handal by hand )

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