9. Find the probability P(140 < x < 149). The μ= 149 and σ= 5.18. Round to 4DP.
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10. Find the probability using the standard normal distribution. Round to 4DP.
P(z < −1.35 or z > 1.35)
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For 12 – 15, round to 2DP.
12. Find the z-score for which 70% of the area is to the right. ________
13. Find the z-score that corresponds to P6. ________
14. Find the z-scores for which 60% of the distribution’s area lies between − z and z.
You may want to sketch a drawing.
________
9. Find the probability P(140 < x < 149). The μ= 149 and σ= 5.18. Round...
1) Find the area under the standard normal curve to the right of z= -0.62. Round your answer to four decimal places. 2) Find the following probability for the standard normal distribution. Round your answer to four decimal places. P( z < - 1.85) = 3) Obtain the following probability for the standard normal distribution. P(z<-5.43)= 4) Use a table, calculator, or computer to find the specified area under a standard normal curve. Round your answers to 4 decimal places....
Suppose x has a distribution with μ = 10 and σ = 2. (a) If a random sample of size n = 39 is drawn, find μx, σ x and P(10 ≤ x ≤ 12). (Round σx to two decimal places and the probability to four decimal places.) μx = σ x = P(10 ≤ x ≤ 12) = (b) If a random sample of size n = 56 is drawn, find μx, σ x and P(10 ≤ x ≤...
3.1 Area under the curve, Part I: Find the probability of each of the following, if Z~N(μ = 0,σ = 1). (please round any numerical answers to 4 decimal places) a) P(Z < -1.35) = b) P(Z > 1.48) = c) P(-0.4 < Z < 1.5) = d) P(| Z | >2) =
Suppose x has a distribution with μ = 10 and σ = 9. (a) If a random sample of size n = 35 is drawn, find μx, σ x and P(10 ≤ x ≤ 12). (Round σx to two decimal places and the probability to four decimal places.) μx = σ x = P(10 ≤ x ≤ 12) = (b) If a random sample of size n = 60 is drawn, find μx, σ x and P(10 ≤ x ≤...
Suppose a population of scores x is normally distributed with μ = 150 and σ = 12. Use the standard normal distribution to find the probability indicated. (Round your answer to four decimal places.) Pr(x > 180)
A population of values has a normal distribution with μ=98μ98 and σ=53.4σ53.4. You intend to draw a random sample of size n=201n201. Find the probability that a single randomly selected value is greater than 86.3. P(X > 86.3) = Round to 4 decimal places. Find the probability that the sample mean is greater than 86.3. P(¯¯¯XX > 86.3) = Round to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 2 decimal places are accepted.
X is normally distributed with mean μ= 5.2 and standard deviation σ= 1.4. A. Find the z-score corresponding to X= 7.3. B. Compute P(X≤7.3) C. Compute P(X>7.3)
More Practice With Normal Distributions. Assign your numbers for mean μ and standard deviation σ. Then select a number "A" below mean μ, and a number "B" above mean μ. Use Appendix Table for the Normal Distribution to find probability that x is between A and B: P (A < x < B). Here are steps to follow: convert A to z score (let's call it za), convert B to z score (let's call it zb).; From Appendix table find...
Find μ if μ ΣΙΧ.P(x)]. Then, find σ if σ2 ΣΙΧ2 . P(x)-μ2. 2 5 2 P)0.0002 0.00530.0450 0.19190.4089 0.3487 H(Simplify your answer. Round to four decimal places as needed.) ơ- (Simplify your answer. Round to four decimal places as needed.) Enter your answer in each of the answer boxes.
Consider a normal distribution with mean 25 and standard deviation 5. What is the probability a value selected at random from this distribution is greater than 25? (Round your answer to two decimal places.) Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 14.9; σ = 3.5 P(10 ≤ x ≤ 26) = Need Help? Read It Assume that x has a...