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On a trip, you notice that a 9.10 kg bag of ice lasts an average of...

On a trip, you notice that a 9.10 kg bag of ice lasts an average of 1 day in your cooler. What is the average power absorbed by the ice if the ice starts at 0 °C and completely melts to liquid water at 0 °C in exactly 1 day? Give your answer in units of watts.

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Answer #1

Ty=T; = 0 °C 24K 602 s .. At = 1.0 day= 1.0 day x 10 day * 1.0 K = 8.6 = 8.64 x 104 s .. LF.w = 334 x 103 J/kg From table (1.

We know that the average power is the amount of energy transferred divided by the time taken for the transfer: Pava = W/At Be

P_ miceL, Δt

P = (9.1 * 334*103 ) / ( 8.64*104 )

P = 35.17W

I hope it was helpful..

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