Question

There are 5 senior marketing directors at Acme Anvils. Each is given an annual quota which is the amount of business they are expected to generate that year. Develop a program that prompts the company president to enter the quota for each director and the actual sales generated by each director. After all the data is entered, the program should produce a chart that displays one row for each director. The first number in the row will be the director's quota and the second number in the row will be his actual sales. IF the director's sales exceed his quota, add a third column that represents his bonus. The bonus is 10% of the amount by which the sales exceed the quota. If the director fails to meet his quota, leave the 3^rd column blank.

Your solution MUST include 2 arrays: one array for the quotas and a second array for actual sales. (This is Programming in C)

Answer 1

`Hey,

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#include <stdio.h>

#include <stdlib.h>
int main()
{
double quota[5];
double sales[5];
int i;
for(i=0;i<5;i++)
{
printf("Enter quota for %d director\n",i+1);
scanf("%lf",&quota[i]);
printf("Enter sales for %d director\n",i+1);
scanf("%lf",&sales[i]);

}
for(i=0;i<5;i++)
{
printf("Quota: %f\tSales: %f\t",quota[i],sales[i]);
if(quota[i]<sales[i])
{

printf("Bonus: %f\n",(sales[i]-quota[i])*0.1);
}
else
{
printf("\n");
}

}

}

Kindly revert for any queries

Thanks.