Question

Question 4 You just got off a a bus, and 1.15s after it pulls away you realize you left your backpack on board. You immediately run to catch it, accelerating at a constant 4.57 m/s2. The bus accelerates at a sluggish 1.03 m/s2. How long, in seconds, does it take you to catch up to the bus door? 1.04 margin of error +/-0.05 Find the time at which the positions of the bus & pedestrian are the same. You will need to account for more than one time, since each is travelling for a different amount of time

Answer 1

Let the time be t therefore 1/2(4.57)t^2 = 1/2 times (1.03) times (t + 1.15)^2 => 4.57t^2 = 1.03 times (t + 1.15)^2 => 2.11t = t + 1.15 => t = 1.15/1.11 = 1.04 s