Question

3-5. An ideal liquid mixture of benzene and toluene (50% by volume each) is used in a plant at 27°C and 1 atm. Determine (a) the mixture TLV, (b) the evaporation rate per unit area for this mixture, and (c) the ventilation rate required to keep the concentration below the TLV if the liquid is contained in a drum with a bung diameter of 5.1 cm. Assume the ven- tilation quality within the vicinity is average.

Answer 1

Solution: values are ay From the given table the TLV Вmле. о. С PPT То име: 0 Рем Datamination of mixture TLV: Using the formula, - (TLV-TWAJ mix = Eu mx Antoine Brenzene: Equations: enprat , 18:9 - 2788.5 T-52-36 To leene: dupsar = 160 - 3096 In T-53-67 where peat is in mm Hg and Tink

Т. 2ъс съоъ k Bewme LP 10. — 2700-г 3от -2-34 peat = 103.5 mm Hg Tь аме: Д-р М. - 16-о — 30ч6 3 – 53-67 prat z 30.93 mmhg Partial bensene Toluene: pressures: p = (0.5) (103.5 mmitg) = $1.75 mm Hal P2 z(0.8) ( 30.03 mmHg) = 15. 46 mm Hg Total pressure, P= 1 atm = 760 mm Hg с е 42-5 м м * 66, 6:01 x 16" рем to mm ty с, ? is. ut muuttg — "ко= 2-D2х1о“ рем Now, Tuv TwА) 2 6 8 1X 10*2. Ф2х урч 6 .81x16" 2.3x104 . — Т . р- по 2 б. (ич РР м

b) Determination of per unit area of evaporation mixture; rate Qm = MKA (xi pret в, т. Qu - MK chipiraty Rg Ti 1 - Estimate k from equation, KZ kol mass Taking watch as reference whose ko value is 0.83 cupsec. Benzene: K= (0.83 anysee) ( 18 ) zeine ! ka 70.1U = 0.509 anysec . Toluene; K = (0.83 urlsed li 192. Evaporation Benrence: 2 0.482 any sec rate Qm z (78.11 8/male) (0.509 any sec) (1 : 1 atm) À (02.06.com's eten. Et molt) ( 300 kg 21.0998104 g into see M at

T • 15.46 toluene Toluene! am = (92-11 & mole (0.482 un sec) ( 's ubi ating (82.06 cm.atm.ki mot') (300K) 23.67x10-s g . cueosec Total evaporation rate = (10.99$3.67) x los = 14.668100 unisec - Oppm 2 Qm Rg T - k Qu PM in - X 106 where; Uppin a mixture Thiva 0,644 ppm. Rg z 82.6 une atm. KY molt T2300k .pal atm lis. 46 l . Is 1.75+15:46) lis.46+81.75 41.75 M=1 51.75 le +1 15:46 z 81.83 Timote Se Qu = (14.66810( 7 (s.16m") = 2.99x109 Ventilation rate C Qu z Qm Rg Ty 106 2 w k Uppm Pm?

Qu z (2.99X103 ) MC82.06 cm'.atm.mot "k4)(300K) 16 k (0.644 )* (1 atms( 81.33 g Imole) Qv z 1405359.12 en - k sec for these conditions, kz 1 Quz 1405359012 Y8 - 11 24 Xlot com I Qua ill. This is very practical large and probably not very