Question

MULIMI Umplicated than the hrst assignment. Write a program that will let the user enter an integer. If the integer is less than 5 make the actual input value be 50. We will call the value that the user put in N. Print the integers from 1 to None number on each line. If the number you are going to print is divisible by 3 print the word fuzz instead of the number. If the number is divisible by 5 print the word buzz instead of the number. If the number is divisible by both 3 and 5 fizzbuzz should be output.

Answer 1

As you not specified any language to code this, so first i am providing you the pseudo code of this program as if you want to code in other language then you can use this pseudo to make required function then i will provide you the c++ code of this program.

Pseudo code:

===========================================================================

function printNumberTill( N )

step 1. i = 1 repeat step 2 to 8 until we get i>N and increment i.

step 2. If i is divisible by both 3 and 5 then

step 3. print "fizzbuzz"

step 4 otherwise. if i is divisible by 3 then

step 5. print "fizz"

step 6. otherwise if i is divisible by 5 then

step 7. print "buzz"

step 7. otherwise

step 8. print i

==============================================================

I hope you understand above pseudo code.

below is my c++ code.

=================================================================

#include<iostream>

using namespace std;

// Function to print number or fizz or buzz or fizzbuzz on each line till n

void printTillN(int n){

// Iterating till i becomes equal to n

for(int i=1;i<=n;i++){

// checking condition is i is divisible by both or not

if(i%3==0 && i%5==0){

// printing the fizzbuzz

cout<<"fizzbuzz"<<endl;

}else if(i%3==0){ // checking condition is i is divisible by 3 or not

// printing the fizz

cout<<"fizz"<<endl;

}else if(i%5==0){ // checking condition is i is divisible by 5 or not

// printing the buzz

cout<<"buzz"<<endl;

}else{ // else we just print the number itsself

// printing the number itself

cout<<i<<endl;

}

}

}

// Driver function

int main(){

//Declaring the variable

int n;

cout<<"Enter an Integer : ";

// taking input from the user

cin>>n;

// checking if n is less than 5

if(n<5){

// then assigning 50 to n

n = 50;

}

// calling the printing function

printTillN(n);

return 0;

}

====================================================================

Screenshot of my code edior.

An output of the above code.

I hope this will help.
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