Question

es a . the data for a 4 set-up differential leveling loop, that besins and ends on Bm A (308.23), is provided in the table beOM 6ol,03 besins below and All The data for a 4 set-up differential leveling loop, that ends on BM A (308.23), is provided in

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Answer #1

Formula used :

HI= Elevation +BS

Elevation= HI(prev. row) - FS

station BS HI FS ELEVATION
BM A 10.53 308.23+10.53 =318.76 308.23
TP 1 8.57 315.8+8.57=324.37 2.96 318.76-2.96=315.8
TP 2 9.01 319.71+9.01=328.72 4.66 324.37-4.66=319.71
TP 3 1.51 317.03+1.51=318.54 11.69 328.72-11.69=317.03
BM A 10.35

318.54-10.35=308.19

(ACTUTAL=308.23)

CHECK

\small \sum BS =29.62  \small \sum FS =29.66 \small \sum BS-\small \sum FS = 29.62-29.66 = -0.04

LAST ELEVATION- FIRST ELEVATION = 308.19-308.23= -0.04

AS \small \sum BS-\small \sum FS =LAST ELEVATION- FIRST ELEVATION =-0.04

HENCE TABLE PREPARED  IS OK.

MISCLOSURE = 648.47-648.51 = -0.04

order of levelling

length of circuit = 1200/5280 =0.22727 mile

error = 0.04 ft

for first order levelling permissible error =0.01770.22727 ft. =0.008 ft

for second order levelling permissible error =0.03570.22727 =0.0167 ft

for third order levelling permissible error =0.0570.22727ft=0.0238 ft

AS error is more than permissible error in all orders, the order is higher than three orders (fourth order of levelling)

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