Homework Answers
ΔHo = -16.2 KJ/mol
ΔSo = -28 J/mol.K
= -0.028 KJ/mol.K
T= 450.0 oC
= (450.0+273) K
= 723 K
use:
ΔGo = ΔHo - T*ΔSo
ΔGo = -16.2 - 723.0 * -0.028
ΔGo = 4.04 KJ/mol
Since ΔGo is positive, the reaction is non spontaneous
Answer: No, it is NOT spontaneous
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