The plastic block is subjected to an axial compressive force of F 400 N. (Figure 1)...

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The plastic block is subjected to an axial compressive force of F 400 N. (Figure 1) The caps at the top and bottom distribute

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160 N # EFx = 0 Ž V - 460 sin 30 =0 = v= 230 N # EFY = 0 » N-460 Cos 30 =0 > N = 338 37 N 130° 100 + 7 100 = Cos 30 30 - »

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The plastic block is subjected to an axial compressive force of F 400 N. (Figure 1)...

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