Question

Ch I. Keys to the Study of Chemistry 1. Unit conversion. 2.5 pts) 2A. Convert 862.35 torr to atm and mmHg (I atm 760 mmHg) 2B. Convert 365.00 Liters to ml. 0 mL). 2C. Convert 4.536 g to mg and kg (I kg 10 g. g 10 mg). 2D. Convert 25.12 oC to Kelvin. 2E. Convert 25.12 OC to Fahrenheit (in F) 9/5 T (in oC)+ 32) 2F. Convert 1.65 m to nm (1 m 0 nm). 2G. Convert 75 miles to m (1 mile .6 km. 1 km 10 m). 2H. Convert 2.54 m to inch (I in 2.54 cm. 1 m 00 cm) 21. Convert 2.54 gal to liters (IGal 3.80 L) 2J. Convert 2.54 Hz to s
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Answer #1

2A)

Given P = 862.35 torr

1 torr = 0.001316 atm

then

862.35 torr = 0.001316 x 862.35 atm = 1.135 atm

1 atm = 760 mmHg

then

1.135 atm = 760 x 1.135 mmHg = 862.49 mmHg

2B)

365.00 L to mL

1 L = 103 mL

then

365 L = 365 x 103 mL = 365000 mL

2C)

4.536 g to mg and Kg

1 g = 103 mg

then

4.536 g = 4.536 x 103 mg = 4536 mg

1 Kg = 103 g

then 1 g = 10-3 Kg

so 4.536 g = 4.536 x 10-3 Kg = 0.0045 Kg

2D)

25.12 0C to Kelvin

We know that 0 0C = 273.15 K

then

25.12 0C = 25.12 + 273.15 = 298.27 0C

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