Question

The steel beam ABCD shown in the figure is simply supported at Cand supported at Band D by shoulder steel bolts, each having a diameter of 10 mm. The lengths of BE and DF are 50 mm and 60 mm, respectively. The beam has a second area moment of 21 x 103 mm4. Prior to loading, the members are stress free. A force of P= 2000 N is then applied at point A. Using procedure 2 of Sec. 4– 10, determine the stresses in the bolts and the deflections of points A, B, and D. D Hz F -75 mm 75 mm 75 mm

Answer 1

Given 우 4 7 Sum 75mm R 75mm R2 B! D F ABCD is a steel beam Dia of BE - Dia of DF = D = lomm Length of BE of DF = 60mm length Moment of rea beam = 21 x 10²mm" P=2000N let reaction in BE & DR are R & R2 CS Scanned with CamScanner balance Applying moment about

moment of 1) (moment of f) + (moment of R₂) So, P (150) = R, (75) + R₂ (75) 2P = R + R₂ due to Albled' is position Now deformation. ACC so, figure. BA' = are same. in both the bolt So Deformation So, R = R₂ from Ri= R₂ = P = 2ooon Load in bolts = stresses So, Area Area 2000 (* 8000 (3) = 10 mm] Sol T (oo) CS Scannso, wears more

Deflection BE = RL (S) AE R, Reaction at B oos L length of Be cross of (0.002 BC Elasticity moduly So, (1) = @ooo) (0.05) Coola m 1.27 X106 6 points So Deflection of 127x106 E is & cool are congonent And ACAA In 50 AA! 150xd sol ADE 75 2 x 12 293106 AA = as= so m at A = 2.54 x lot CS Scanse mettent eamScanner E