Question

A 2.08 m -long coil containing 225 loops is wound on an iron core (average mu = 1850 mu_0) along with a second coil of 115 loops. The loops of each coil have a radius of 1.10 cm. If the current in the first coil drops uniformly from 12.0 A to zero in 96.0 ms. Determine the mutual inductance M. M = Determine the emf induced in the second coil. e_2 =

Answer 1

Area of the coil A = π×(0.011)2 4-3.8×10-4 m2 Value of μ = 1850×4m x 10-7 μ = 2.32 x 10-3 Part A Mutual Inductance of the coil M= 2.32×10-3×3.8×10-4 × M = 0.01 09 H M= 10.9 mH 2.08

Part B emf induced in the second coil dI dt є -001098-12 E0.0109 96x10% 1.3625 V