Question

Please include work. I'd like to know how to solve them.

1.) Consider a charged particle moving through a region in which the electric field is perpendicular to the magnetic field, with both fields perpendicular to the initial velocity of the particle (see figure below). Such a device is called a velocity selector because for one particular value of the particle speed vselect the particle will travel straight through the device without being deflected, whereas particles with speeds that are either less than or greater than vselect will be deflected. Consider a case with E = 525 V/m and B = 0.28 T.

(a) When protons are used, what speed is selected? m/s (b) What is the speed selected for Ca2+ ions?

_______m/s

(b) What is the speed selected for Ca2+ ions?
_____m/s

thank you so much for your help!!

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Answer #1

A) at equilibrium FE = FB ie qE = qVB Or V = E/B = 525/0.28 = 1875 m/s

B) Speed will remain same as it doesn;t depend upon charge

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