a)
concentration of Ag+ = 0.0340 M
Ksp of Ag2SO4 = 1.20 x 10^-5
Ksp = [Ag+]^2 [SO42-]
1.20 x 10^-5 = (0.0340)^2 [SO42-]
[SO42-] = 0.01038 M
CaSO4 ------------> Ca+2 + So42-
Ksp = [Ca+2][SO42-]
4.93 x 10^-5 = [Ca+2] [0.01038]
[Ca+2] = 4.75 x 10^-3 M
b)
% Ca+2 remaining = (4.75 x 10^-3 / 0.05 ) x 100
= 9.50 %
% of Ca+2 that can be seperated = 100 - 9.50
= 90.5 %
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