Question

A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 3.26 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 1980 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 5.92 V/m, (b) in the negative zdirection and has a magnitude of 5.92 V/m, and (c) in the positive x direction and has a magnitude of 5.92 V/m?

Answer 1

Magmctic forcc cing ou a chorge (g partick is YC as 9 Magctfore r i a'14 (1980 Y 3 I 6 X0 -19 10. 32 x \0. N di vecte d olowg busi ive 3 divecdion Eleclvic fovce 5.92X1GXI0* 19 bi- 2- dumection Since electric field is divccted aa-^ net forc is -9 10.32 10 + 9.472x 10 b) Electc foc 9.472 x I0 9 5.92 x lo 4 divecled abmg 2 dcton, met frrce is Sa N 0. 855 X10 9.472 XIC I0.327 xio9 El cetvi forrc 9.47210 c.) herp direction and a lo ng red fu ce (10. 14.01 x 10- 9