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(a) What is the electric potential energy of two electrons separated by 2.13 nm? (b) What would be it be if the separation wa

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q = 92= -e d = 2.13 nm Energy - kte) (-e) E.P.E = 6 x 10 -19) 9 x 109)(-1,6% 2.13x109 - 20 10.8/69 x 10 Joule b a Now 82 28

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