Estimate the boiling point elevation of 0.39 m NaCl(aq), assuming it undergoes complete dissociation. The boiling point constant of water is 0.51 K · kg/mol.
Answer in units of ◦C.
Given
Solutuion of NaOH is 0.39 m
Molar mass of NaOH is 58.44 g /mol
The boiling point constant of water is 0.51 K · kg/mol.
Number of particals will be 2 x 0.39= 0.78 m
1.0 molar solution increases boiling point by 0.51K
0.78 m solution will increase boiling point by: 0.51 x 0.78
=0.3978 °C is elavation in BP.
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