Convert the for loop into MIPS instructions. Use the slt instruction to determine the branch. Be sure to initialize i properly.
for (int i = 1; i < 7; i++)
value = value + i;
i: $t0, value: $s0
MIPS instructions for above loop:
li $t0, 1 # t0 is initialized to 1
loop: # it is label for loop
add $s0, $s0, $t0 # value of t0 is added to s0 and stored back in s0
addi $t0, $t0, 1 # t0 is incremented by 1
slt $t1, $t0, 7 # If t0 < 7 then t1 = 1, otherwise 0.
bne $t1, $zero, loop #if t1 = 0 then the loop will exit, else it will continue
Convert the for loop into MIPS instructions. Use the slt instruction to determine the branch. Be...
The following MIPS branching pseudo instruction bge $s0, $s1, Label # branch to Label if $s0 is greater or equal $s1 will be translated to these two native instructions by the MIPS assembler: slt $at, $s0, $s1 [a] $at, [b], Label Fill for [a] and [b]? Please explain aswell
Convert the following MIPS instructions Into Machine Code Instructions. Assume the first Instruction starts at memory address 20000 slt $t1, $s1, $s0 beq $s1, $s2, L1 beq $t1, $zer0, L2 j Exit L1: add $s1, $s1, $s1 j Exit L2: add! $s1, $s1, 1 Exit:
Consider the following MIPS code (don't worry about what it does): loop: beq $s0, $s1, done addi $t0, $t0, 7 addi St1, St2, 4 addi $s0, $s0, 1 j loop done: beq St1, $15, skip addi St0, Sto, 1 addi St1, St2, St0 skip addi $t5, $0, 10 beq St1, St5, done j end Compute the branch offset for each beq in number of words away from the branch (e.g., "branch offset is 2") Assume label loop is at location...
B2. Convert the C code to MIPS assembly with only 2 efficient instructions: Register assignment: timer-v0 int timer = 0x0AC8 0001; B3. Write MIPS assembly code segment for the following C code snippet for (i - 0, i < 100; i++) -array Register assignment: i-) $ao Base of array -> $s0 array [ i+1] [i] / 2; B2. Convert the C code to MIPS assembly with only 2 efficient instructions: Register assignment: timer-v0 int timer = 0x0AC8 0001; B3. Write...
Reschedule (i.e., re-order) the instructions within the loop to improve performance. The loop must still produce the same results. Show timing of this MIPS instruction sequence through the pipeline, for two iterations of the loop. Show all stalls clearly, and mark with arrows all cases where forwarding takes place, as in our lectures. loop: lw $t0, 0($s0) lw $t1, 4($s0) add $t0, $t1, $t0 sw $t0, 0($s1) addi $s0, $s0, 8 addi $s1, $s1, 4 bne $s0, $s5, loop
Please answer all questions 6. T/F On MIPS-32 architecture, branch instructions "bgt" and "ble" can be directly executed by the processor 7. On MIPS-32 architecture, the field of an instruction specifies the shift amount. 8 register points to the next instruction to be executed. 9. The special register specifies the address of instruction to be fetched and executed. 10. R-type instructions use 1. A caller function uses the 12. The instruction "jr" is a(n) addressing mode. instruction to call a...
2. The table below holds MIPS assembly code fragments with different branch instructions LOOP addi $s2. $s2. 2 subi $t1. st1. 1 bne t1. 0. LOOP DONE: LOOP: it st2. $0. stl beq t2. 0. DONE addi $s2. Ss2. 2 LOOP DONE: For the loops written in MIPS assembly in the above table, assume that the register Şt1 is initialized to the value of 10. What is the value in register $s2 assuming that $s2 initially has a value of...
Question 29 3 pts MIPS branch instructions compute their destination by subtracting the branch address from PC 4 True False Question 31 3 pts PC-relative addressing cau cover (access) the whole memory space of MIPS. True False Question 32 2 pts If the current vlue of the PC is Ox00000000. you can use a single jump instruetion to get to the PC address as Ox00100400. True False Question 35 2 pts What is the comrect value for? in the following...
Convert the following high-level language into MIPS instructions. Please write comments for each instructions. Assume a, b, c, d are associated with registers $s0, $s1, $s2, $s3, respectively. void main () { int a = 10, b = 20; int c = add(a, b); int d = sub(a, b); swap (a, b); } int add( int var1, int var2) { return (var1 + var2); } int sub(int var1, int var2) { return (var1 - var2); } void swap(int var1, int...
Question 3 (10 points) Convert the following MIPS assembly code into machine language. Write the instruction in hexadecimal. The opcode for sw 43 (101011). sw St1, -4(St3) Question 4 (10 points) Consider the following MIPS assembly code: addi $s3, $0, 5 addi $s1, S0, 3 addi Ss1, $s1, 2 beq Ss3, Ssl, target addi Ss1, Ss1, 1 target: add Ss3, Ss1, Ssl a. After running the code, what is the value of Ss3? b. If the memory address of the...