Question

2. Let's return to the paintball game introduced in class, being played by Jodie and Peter. At point, Peter returns to the platform, 5 metres above the ground, and spies Jodie lying on the ground next to a blue box 50 metres away. He shoots a paintball at Jodie with a speed of 20 metres per second at an along the ground, to one decimal place. Is this an undershoot, an overshoot, or a direct hit? one angle of 30°. Determine how far the paintball travels

Answer 1

Horizontal distance traveled = 20 cos 30 degree times t where t is time of flight let t be time taken to reach max height v = u - g t t_1 = 20 sin 30 degree = 1.02 sec v = 0 at max height time to reach at height 5m from the max height = t_2 = t_1 = 1.02sec velocity at this point = 20 sin 30 degree m/s t_3 = time taken to reach ground from height h. 5 = 10t + 1/2 times 9.81 times t^2 5 = 10t + 4.905t^2 5 = 10t + 4.905t^2 t_3 = 0.425 sec therefore 4.905t^2 + 10t - 5 = 0 Total time taken = t_1 + t_2 + t_3 = 2.46 sec horizontal distance = 20 cos 30 degree times 2.46 = 42.6m which is < 50m hence t is an under shoot