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Charges of 6.0 nC, -7nC, 2.0 nC and -4.0 nC are contained inside a rectangular box with length 1.0 m, width 2.0 m and height
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Answer #1

according to gauss law

electric flux = charge enclosed/ permittivity of free space

= q / eo

= (6 - 7 + 2 - 4) *10^-9 / 8.85*10^-12

= 3.39*10^2 N.m^2 / C

so option c) is the correct answer

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