Question

Write a C program to display the output below. Not: Use for loop only. ... ******** TT T Arial 3 (12pt) T-E- E - 3.

Answer 1

Solution:

Explanation:

#include <stdio.h>

#include <stdio.h>

int main()
{
    int i,j; //declaration of variable i and j
    for(i=0;i<7;i++){ // looping 7 times from i = 0 to 6 for 7 lines
        for(j=i;j<13-i;j++){ // looping 13 times from j = i to j = 13-i for printing *
            printf("*"); //printing *
        }
        if(i != 6){ //if i ! = 6 then changing line
        printf("\n");
        }
      
        for(j=0;j<i+1;j++){ // printing space based on i value
            printf(" ");
        }
      
    }
    for(i=7;i>0;i--){ //looping 7 times for 7 lines
        for(j=0;j<=i-1;j++){ //printing spaces based on value of i
            printf(" ");
        }
        for(j=13-i;j>i;j--){ // looping based on value of i and j
           printf("*"); //printing *
        }
        printf("\n"); //changing line
    }
    for(i=0;i<5;i++){   // looping 5 times from i =0 to i =4 for 5 lines
        for(j=0;j<4;j++){ // looping 5 times from j = 0 to j= 4
            printf(" "); //printing spaces
        }
        for(j=0;j<5;j++){ //looping 5 times from j =0 to j=4
            printf("*"); //printing *
        }
        printf("\n"); //changing line
    }

    return 0;
}

5 int main() int i, j; for(i=0;i<7;i++){ for(j=i;j<13-i;j++){ printf("*"); if(i != 6){ printf("\n"); for(j=0; j<i+1;j++){ printf(" "); for(i=7;i>0;i--) { for(j=0; j<=i-1;j++){ printf(" "); KOO VOULAWNHOLD VOWNLOVOU AWNHO for(j=13-i;j>i;j--){ printf("*"); printf("\n"); for(i=0;i<5;i++){ for(j=0; j<4;j++){ printf(" "); for(j=0; j<5; j++){ | printf("*"); printf("\n"); return 0;

***** ***** *** ********* ポポポポポポポ**** ポポポポポポポポポポポポポ $main $gcc -o main *.c

I have explained each and every step with the help of code with comments attached at the right of every statement and also attached the code of compiler with the output of compiler.