Question

Bowling balls are roughly the same size but come in a variety of weights. Given that the official radius a bowling ball should have is roughly 0.111 m, calculate the weight of the heaviest bowling ball that will float in a fluid of density .100 x 10 kg/m3. weight:

Answer 1

Here ,

for the radius

r = 0.111 m

for the weight of the ball

weight of the ball = weight of displaced water

weight of the ball = 4pi/3 * r^2 * density * g

weight of the ball = 4pi/3 * 0.111^3 * 1.1 *10^3 * 9.8

weight of the ball = 61.74 N

the weight of the ball is 61.74 N

Answer 2

The weight of the ball is, π(0.111m). |(9.8 m/s 1.1x10* kg/m -61.75 5 N 61.75 N