Question

(a) If the cost of electricity consumption in Oman is OR 0.030/unit (where, 1 unit = 1 KWH), Calculate the monthly electricity bill for a load usage of 10 lamps (15 watts each), 10 fans (1000 watts each) and 1 TV (2000 watts) for 18 hrs. a day. [3 marks] (b) Calculate the efficiency of a solar PV module whose length is 259 cm and width is 110 cm and produces a 2560 W maximum power when exposed to 920 W/m² solar irradiance? [2 marks]

Answer 1

(7) a.) solh Ginen, No. of lamps = 10 No. of fors = 10 → TN = 1 (in number) → Rating of I bmp = 15w Rating of 1 fan = 1000w Rating of 1 TV = 2000 w All the appliances work for 18 has a day Now, we calculate total power rating of lo lamps for 18 has a day I 18x10x15 W = 270ow Total power rating of to fans for 18 has . a day. 0= 1 8 x 10 xlovo = 180orow Total power dating of 1 TV for 18 has a day > 360ow Overall power consumed by all the loods for 18 has a day = 2700 + 18 000 + 36 ovo = 218700 W = 218.700kW These fore, total power consurned for I ho = 218. 7.00 kW = 12.15 KWH = 12.15 units Now, cost of 1 unit is or 0.030 . Cost of 12.15 units is or 0.030812-15 18 Total cost of 12 15 units = OR 0 364 bo Sol Length of PV module = 25gem - Width of pv module = 110cm There fore, Total area of PV module = 259x110 m² = 259 xliem? 100 x100 = 2.849 m² It is given, Solarissadiance =920 W/m² Honce, for lm² solar irradiance is grow . For 2.849 m² solar irradiance is, - 20849 X 920w = 2621.08 w Input power = 262108 w Output power = 2560w (ginen) --/Efficiency (2) - Outlet E Input Power 2560 x 100% 2621:08 97.66% = Scanned with CamScanner cs Scanned with CamScanner